SOURCE SPORTS: Seattle Seahawks Makes Jamal Adams Highest Paid Safety After Agreeing On a 4 Year Extension

Jamal Adams is staying in Seattle for the foreseeable future. Adams will sign a four-year, $70 million contract extension with the Seahawks, according to Ian Rapoport of NFL Media. The deal makes Adams the highest-paid safety in the NFL and includes $38 million guaranteed.

The #Seahawks have agreed to terms on a large extension for star S Jamal Adams, a 4-year, $70M deal that makes him the league’s highest paid safety, I’m told. He gets $38M guaranteed, breaking the stalemate. A long time coming and well-deserved. ???

— Ian Rapoport (@RapSheet) August 17, 2021

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Adams is now by far the top-earning safety in football with an average annual salary of $17.5 million. Justin Simmons was previously atop the list, and he earns an average of $15.25 million per year with the Denver Broncos.

Adams was a first-team All-Pro selection in 2019 and has been named to the Pro Bowl in each of the last three seasons. He set the league’s single-season record for sacks by a defensive back last year with 9.5.

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Seattle traded two first-round picks to the New York Jets for Adams last year. If the Seahawks didn’t resign Adams, then those picks would have been gone for nothing.